以下代码是登录Action中一段，使用StrutsTestCase该如何进行单元测试？
重点问题是
tusers = udao.findWhereUserIDEquals(userID);
这里的findWhereUserIDEquals()方法会在数据库中进行查找，测试时不好操作
UserLoginAction.java复制内容到剪贴板
代码:
public ActionForward login(ActionMapping mapping,ActionForm form, HttpServletRequest request,HttpServletResponse response)throws Exception{
String userID = WebParamUtils.getParameter(request, "userID", "");
String password = this.getParameter(request, "userpass", "");
TbFilesystemusersDao udao = TbFilesystemusersDaoFactory.create();
TbFilesystemusers[] tusers = null;
TbFilesystemusers tuser = null;
try{
tusers = udao.findWhereUserIDEquals(userID);
if(tusers == null || tusers.length == 0){
request.setAttribute("message", "请您输入正确用户名及密码！");
return mapping.findForward("logout");
}
tuser = tusers[0];
request.setAttribute("userid", username);
if( !password.equals(tuser.getUserPwd().trim())){
request.setAttribute("message", "请您输入正确用户名及密码！");
return mapping.findForward("logout");
}
Role roles[] = rdao.findWhereRoleCodeEquals(tuser.getUserrole());
Role role = null;
if(roles != null && roles.length > 0){
role = roles[0];
}
request.getSession().setAttribute(Const.ROLE, role);
request.getSession().setAttribute(Const.LOGIN_USER, tuser);
}catch(Exception ex){
ex.printStackTrace();
request.setAttribute("message", "请您输入正确用户名及密码！");
return mapping.findForward("logout");
}
return mapping.findForward("success");
}有想法使用MockStrutsTestCase来测试，自己写了个MockUserLoginAction继承上面的UserLoginAction
代码如下：
复制内容到剪贴板
代码:
public class MockUserLoginAction extends UserLoginAction{
public ActionForward login(ActionMapping mapping,ActionForm form,HttpServletRequest request,HttpServletResponse response)throws Exception
{
String username = WebParamUtils.getParameter(request, "username", "");
String password = this.getParameter(request, "userpass", "");
System.out.println("username");
System.out.println("password");
if(username == null || username.length()== 0){
request.setAttribute("message", "请您输入正确用户名及密码！");
return mapping.findForward("logout");
}
if(username!="8000"||password!="123456")
{
request.setAttribute("message", "请您输入正确用户名及密码！");
return mapping.findForward("logout");
}
request.setAttribute("userid", username);
return mapping.findForward("success");
}
}测试类代码如下：复制内容到剪贴板
代码:
public void testLoginSuccess() throws Exception
{
STCRequestProcessor.addMockAction("com.zzy.record.action.user.UserLoginAction","com.zzy.record.action.user.MockUserLoginAction");
setRequestPathInfo("/loginAction");
addRequestParameter("method","login");
addRequestParameter("username","8000");
addRequestParameter("userpass","123456");
actionPerform();
//verifyForward("success");
assertEquals("8000",this.getMockRequest().getAttribute("userid"));
}
但运行出错
错误信息如下：
Caused by: javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file: java.naming.factory.initial
at javax.naming.spi.NamingManager.getInitialContext(Unknown Source)
at javax.naming.InitialContext.getDefaultInitCtx(Unknown Source)
at javax.naming.InitialContext.getURLOrDefaultInitCtx(Unknown Source)
at javax.naming.InitialContext.lookup(Unknown Source)
at com.zzy.record.jdbc.ResourceManager.getConnection(ResourceManager.java:13)
at com.zzy.record.jdbc.TbFilesystemusersDaoImpl.findByDynamicSelect(TbFilesystemusersDaoImpl.java:1029)
... 34 more
有没有其它办法可对其进行单元测试？
万分感谢！！！
