SQL server 查询问题

roadxizi

好的,谢谢

ecust

原帖由 roadxizi 于 2007-1-29 11:50 发表
(姓名 = 'ecust')  感觉不对,因为不知道谁走的最晚,

WHERE 条件里怎么就固定了姓名了呢?

你不是要知道每个人么？
就有了姓名的条件，下面的姓名嵌套查询加进去就会有不同的名字进去。
查找出不同的人每天的最晚的记录。
如果你要知道谁最晚，而不是每一个人的最晚，那去掉where的条件就可以了

roadxizi

说的我都快不明白了.

我是要每个人的最早和最晚记录，

到是可以按照姓名分组,所有员工某天的最早和最晚记录都出来

sunxy5291

2、3我是不会了
不过我帮你问问别的高手！

ecust

纯SQL写是一个很痛苦的事情，我感觉。。。
干吗要这种方式列。。。

sunxy5291

2.
迟到分钟：
select 姓名,DATEDIFF(minute,cast((convert(char(10),日期时间,120) + ' 09:00:00') as datetime),日期时间) as 迟到分钟 from table1 where not exists (select id from table1 where 姓名 = a.姓名 and 日期时间 < a.日期时间) as a

早退分钟：
select 姓名,DATEDIFF(minute,日期时间,cast((convert(char(10),日期时间,120) + ' 18:00:00') as datetime),) as 迟到分钟 from table1 where not exists(select * from table1 where 姓名 = a.姓名 and 日期时间 > a.日期时间) as a

roadxizi

修改以后对了,谢谢了

sunxy5291

对了？
那你都修改什么啦
发出来

roadxizi

select 姓名,DATEDIFF(minute,cast((convert(char(10),日期时间,120) + ' 09:00:00') as datetime),日期时间) as 迟到分钟

from [考勤报表] a

where not exists

(

select id from [考勤报表]

where 姓名 = a.姓名

and 日期时间 < a.日期时间

)

sunxy5291

把所有的都类出来，这里是bbs你要让大家都学习啊！

roadxizi

set ANSI_NULLS OFF
set QUOTED_IDENTIFIER ON
GO
ALTER PROCEDURE [dbo].[get_yuangong_chidao_xx_cdzt]
(
        @name varchar(100),
        @date datetime,
        @type varchar(100)
)
AS


declare @Year int,@Month int,@Day int,@Minute int,@Minute2 int
set @Year=year(@date)
set @Month=month(@date)
set @Minute=9*60+3
set @Minute2=18*60+3

if @type='迟到统计'
begin
select [姓名],[编号],[日期时间],[type],[type2],DATEDIFF(minute,cast((convert(char(10),[日期时间],120) + ' 09:00:00') as datetime),日期时间) as '分钟数'
from
(
        select *,'迟到' as [type],day(DATEADD("Day",1,[日期时间]))-day(DATEADD("Minute", 0-@Minute, DATEADD("Day",1,[日期时间]))) as [type2]
        from [考勤报表] a
        where
        ID =
        (
        select top 1 ID
        from [考勤报表] b
        where year(b.[日期时间])=@Year and month(b.[日期时间])=@Month and day(b.[日期时间])=day(a.[日期时间]) and b.[编号]=a.[编号]
        order by b.[日期时间] asc
        )
)c

where [type2]=0

and [姓名]=@name

and year([日期时间])=year(@date)

and month([日期时间])=month(@date)

order by [日期时间]

end

else

begin

select [姓名],[编号],[日期时间],[type],[type2],DATEDIFF(minute,[日期时间],cast((convert(char(10),[日期时间],120) + ' 18:00:00') as datetime)) as '分钟数'
from
(
        select *,'早退' as [type],1-(day(DATEADD("Day",1,[日期时间]))-day(DATEADD("Minute", 0-@Minute2, DATEADD("Day",1,[日期时间])))) as [type2]
        from [考勤报表] a
        where ID =
        (
        select top 1 ID
        from [考勤报表] b
        where year(b.[日期时间])=@Year and month(b.[日期时间])=@Month and day(b.[日期时间])=day(a.[日期时间]) and b.[编号]=a.[编号]
        order by b.[日期时间] desc
        )

)c
--where [编号]=208
--and day(a.[日期时间])=1
--order by [编号],[日期时间],[type]

where [type2]=0

and [姓名]=@name

and year([日期时间])=year(@date)

and month([日期时间])=month(@date)

order by [日期时间]

end

sunxy5291

这不是存储过程吗？
你不是3道题目吗，逐一列出不更明了一些！

roadxizi

都列出来也都一样

都是上面的代码

roadxizi

set ANSI_NULLS OFF
set QUOTED_IDENTIFIER ON
GO
ALTER PROCEDURE [dbo].[get_yuangong_chidao]
(
        @date datetime
)
AS
declare @Year int,@Month int,@Day int,@Minute int,@Minute2 int
set @Year=year(@date)
set @Month=month(@date)
set @Minute=9*60
set @Minute2=18*60
select [姓名],[编号],count([type2]) as '迟到早退次数'
from
(
        select *,'i' as [type],day(DATEADD("Day",1,[日期时间]))-day(DATEADD("Minute", 0-@Minute, DATEADD("Day",1,[日期时间]))) as [type2]
        from [考勤报表] a
        where
        ID =
        (
        select top 1 ID
        from [考勤报表] b
        where year(b.[日期时间])=@Year and month(b.[日期时间])=@Month and day(b.[日期时间])=day(a.[日期时间]) and b.[编号]=a.[编号]
        order by b.[日期时间] asc
        )
        union all
        select *,'o' as [type],1-(day(DATEADD("Day",1,[日期时间]))-day(DATEADD("Minute", 0-@Minute2, DATEADD("Day",1,[日期时间])))) as [type2]
        from [考勤报表] a
        where ID =
        (
        select top 1 ID
        from [考勤报表] b
        where year(b.[日期时间])=@Year and month(b.[日期时间])=@Month and day(b.[日期时间])=day(a.[日期时间]) and b.[编号]=a.[编号]
        order by b.[日期时间] desc
        )
)c
--where [编号]=208
--and day(a.[日期时间])=1
--order by [编号],[日期时间],[type]

where [type2]=0

and year([日期时间])=year(@date)

and month([日期时间])=month(@date)

group by [姓名],[编号]

rainyday32

还在学习SQL，上面的这些还需要努力才能看明白阿~

keibi

用临时表很容易处理了

roadxizi

怎么个处理法？