使用lr_out_message出现提示Exception ACCESS_VIOLATION received.

uestcheng

代码：
#include "lrs.h"
#define hardversion "KTG-3-MAIN V3.31 &GSM"
#define softversion "MY-32F103-G V1.3.111115"
#define updatepacketbuff = "0100"



char sendbuf;
char registerPacket()
{



char terminalid;

char *p;

char *i;

int c;



p = &sendbuf;

*p++ = '*';

*p++ = '0';

*p++ = '0';

*p++ = 'e';

*p++ = 'C';



sprintf(terminalid,"%s",lr_eval_string("{ID}"));

*p++ = ',';



c = 0;

while ((hardversion[c] != '\0')&& (c < 20)) {

*p++ = hardversion[c];

c++;

}



*p++ = ',';



c = 0;

while ((softversion[c] != '\0')&&(c < 20)) {

*p++ = softversion[c];

c++;

}



*p++ = ',';

return sendbuf;


}
Action()
{

registerPacket();

lr_output_message("%s",sendbuf);

return 0;
}


提示信息：
Action.c(22): Warning: Invalid parameter detected in function.
Action.c(46): Error: C interpreter run time error: Action.c (46):  Error -- memory violation : Exception ACCESS_VIOLATION received.
Action.c(46): Notify: CCI trace: Action.c(46): lr_output_message(0x012c035c "%s", 42)
.
Action.c(46): Notify: CCI trace: Compiled_code(0): Action()

msnshow

像是语法错误

thirfing

sprintf(terminalid,"%s",lr_eval_string("{ID}"));
ID定义。？
char* sendbuf；