selenium生成的python脚本报错

hergules · 发表于 2011-4-30 23:58:42

pythone脚本：
import random
import unittest
import selenium
import unittest, time, re
class TestSequenceFunctions(unittest.TestCase):
def setUp(self):
self.seq = range(10)

def test_shuffle(self):
null
class TestGoogle(unittest.TestCase):
def setUp(self):
self.verificationErrors = []
self.selenium = selenium("localhost", 4444, "*iexplore", "http://www.google.com/webhp")
self.selenium.start()

def test_google(self):
sel = self.selenium
sel.open("http://www.google.com/webhp")
sel.type("q", "hello world")
sel.click("btnG")
sel.wait_for_page_to_load("5000")
self.assertEqual("hello world - Google Search", sel.get_title())
#self.assertEqual(u'hello world - Google \u641c\u7d22', sel.get_title())
#print sel.get_title()

# def tearDown(self):
#       self.selenium.stop()

if __name__ == "__main__":
unittest.main()

运行报错：
---------- Python ----------
Traceback (most recent call last):
  File "test_google.py", line 17, in <module>
from selenium import selenium
  File "Z:\I\selenium\selenium-python-client-driver-0.9.2\selenium.py", line 170
raise Exception, result
               ^
SyntaxError: invalid syntax

输出完成 (耗时: 0 秒) - 正常终止

selenium版本：
http://selenium.googlecode.com/f ... e-control-1.0.3.zip\selenium-python-client-driver-1.0.1\selenium.py
版本信息：
"""
Copyright 2006 ThoughtWorks, Inc.

Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at

http://www.apache.org/licenses/LICENSE-2.0

Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
"""

为什么老是提示参数错误？