如何点击ITestDataTreeNode中的一个node

hugh_1982

我要点击一棵树 我用
    ITestDataTreeNode[] nodes = ((ITestDataTree)targetTree.getTestData("tree")).getTreeNodes().getRootNodes();
获得了树上的一些nodes
但是因为nodes的名字有重复
请问怎样能点到想要点击的node  
我想通过index来点击,但是返回的nodes[]要怎样调用.click或者其他选择的方法

tthhbbandy

原帖由 nanchi 于 2008-1-9 23:07 发表
...
showTree(cdTreeNode, 0);
...
void showTree(ITestDataTreeNode node, int indent){
...
   int tabCount = ( indent < tabs.length() ? indent :tabs.length() );
...
}

还是几个问题啊：
showTree(cdTreeNode, 0)  //传的是数组参数，常量0，这个0应该是 变量 i 吗。。
void showTree(ITestDataTreeNode node, int indent)  //接收参数却不是数组。。
tabs.length()  //tabs是没有定义

[ 本帖最后由 tthhbbandy 于 2008-1-16 11:32 编辑 ]

nanchi

Hi,hugh_1982!
Following example may be helpful to you.


public void testMain (Object[] args)
{
    //Declare variables for tree
    ITestDataTree cdTree;
    ITestDataTreeNodes cdTreeNodes;
    ITestDataTreeNode[] cdTreeNode;

    //Variables to hold tree data
    cdTree = (ITestDataTree)tree2Tree().getTestData("tree");
    cdTreeNodes = cdTree.getTreeNodes();
    cdTreeNode = cdTreeNodes.getRootNodes();

    //Print out total number of nodes
    System.out.println ("Tree Total Node Count: " +
    cdTreeNodes.getNodeCount());
    System.out.println ("Tree Root Node Count : " +
    cdTreeNodes.getRootNodeCount());

    //Iterate through tree branches; this is a recursive method.
    for (int i = 0;i<cdTreeNode.length;++i)
        showTree(cdTreeNode, 0);
    }

void showTree(ITestDataTreeNode node, int indent)
{
    //Recursive method to print out tree nodes with proper indenting.

    //Determine number of tabs to use - to properly indent tree
    int tabCount = ( indent < tabs.length() ? indent :
    tabs.length() );

    //Print out node name + number of children
    System.out.println(tabs.substring(0, tabCount) +node.getNode() + " (" + node.getChildCount() + " children)" );

    //Determine if node has children; recursively call this same
    //method to print out child nodes.
    ITestDataTreeNode[] children = node.getChildren();
    int childCount = ( children != null ? children.length : 0 );
    for ( int i = 0; i < childCount; ++i )
        showTree(children, indent+1);
}

tthhbbandy

原帖由 hugh_1982 于 2007-5-10 14:59 发表
我要点击一棵树 我用
    ITestDataTreeNode[] nodes = ((ITestDataTree)targetTree.getTestData("tree")).getTreeNodes().getRootNodes();
获得了树上的一些nodes
但是因为nodes的名字有重复
请问怎样能点到想要 ...

getRootNodes
问一下，怎么能获得整个tree的nodes。为什么我只能获得根节点的，返回的数组长度是1，root也只是只根节点吧？

dudejava

通过位置int pointToClick ，来定位节点

dudejava

ScrollGuiSubitemTestObject objectTree = new ScrollGuiSubitemTestObject(getMappedTestObject(treeName));
            
int itemHeight = ((Integer) objectTree.getProperty("itemHeight")).intValue();
int headerHeight = ((Integer) objectTree.getProperty("headerHeight")).intValue();
Rectangle clientArea = (Rectangle) objectTree.getProperty("clientArea");
int clientAreaHeight = (int) clientArea.getHeight();
int viewableArea = ((clientAreaHeight - headerHeight) / itemHeight) - 2;
int pointToClick = (int) (itemHeight * 1.5);
            
ITestDataTree objectTreeData = (ITestDataTree) objectTree.getTestData("tree");
ITestDataTreeNode [] objectTreeRootNodes = ((ITestDataTreeNodes) objectTreeData.getTreeNodes()).getRootNodes();

for (int i = 0; i < objectTreeRootNodes.length; i++) {
objectTree.doubleClick(atPoint(0, pointToClick));
// Perform whatever activity is needed
                
// Viewable area is a number of rows; if the current row is greater, scroll
if (i > viewableArea) {
objectTree.scrollLineDown();
} else {
pointToClick += itemHeight;
}
}

dudejava

顶一下

[ 本帖最后由 dudejava 于 2007-5-23 18:01 编辑 ]

hugh_1982

急啊 哪位朋友给小弟指点一下