appium-python-client中touchAction的perform函数报错

joyceQinTing

from appium.webdriver.common.touch_action import TouchAction


action=TouchAction(self.driver)
action.press(x=600,y=500).move_to(x=600,y=1000).release().perform()

运行的时候报错，错误信息如下：
  action.press(x=600,y=500).move_to(x=600,y=1000).release().perform()  File "build\bdist.win-amd64\egg\appium\webdriver\common\touch_action.py", line 94, in perform    self._driver.execute(Command.TOUCH_ACTION, params)  File "D:\Program Files\Python27\lib\site-packages\selenium-2.48.0-py2.7.egg\selenium\webdriver\remote\webdriver.py", line 199, in execute    response = self.command_executor.execute(driver_command, params)  File "D:\Program Files\Python27\lib\site-packages\selenium-2.48.0-py2.7.egg\selenium\webdriver\remote\remote_connection.py", line 390, in execute    command_info = self._commands[command]KeyError: 'touchAction'


求大神指教！！！！

newer0zhk

楼主搞定没，我也碰到相同的问题了