select student.studentname, aa.* from student,(select studentid as 'id', sum(score) as 'SUM' from score where score.subjectid in (1,2) group by studentid ) as aa where aa.id = student.studentid order by SUM desc limit 10;
上面语句中的1,2指的是语文数学的id。我自己建表的时候写的语文数学ID是1,2.这里改成你自己的id。
我运行了一下是可以得到你想要的结果的。几年前学的知识都忘没了。。。惭愧啊。。
select * from (select a.*,rownum rm from
(select min(st.studentid) "学号",st.studentname "姓名",sum(sc.score) "总分"
from student st,subject1 su, score1 sc
where st.studentid=sc.studentid and su.subjectid=sc.subjectid
and su.subjectname in('china','math') group by st.studentname order by sum(sc.score) desc
) a) where rm<=10;
select * from (select a.*,rownum rm from
(select min(st.studentid) "学号",st.studentname "姓名",sum(sc.score) "总分"
from student st,subject1 su, score1 sc
where st.studentid=sc.studentid and su.subjectid=sc.subjectid
and su.subjectname in('china','math') group by st.studentname order by sum(sc.score) desc
) a) where rm<=10;
我做的有点麻烦,里面有两个子查询,还用到了伪劣。
技术不精,望指教。