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秀技能:Python绘制表白玫瑰花

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发表于 2022-10-27 15:44:27 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
一、玫瑰花绘制—深红色



  import numpy as np

  import matplotlib.pyplot as plt


  from mpl_toolkits.mplot3d import Axes3D


  fig = plt.figure()


  ax = fig.gca(projection='3d')

  [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 30 * np.pi - 4*np.pi)


  p = (np.pi / 2) * np.exp(-t / (8 * np.pi))


  change = np.sin(20*t)/50


  u = 1 - (1 - np.mod(3.3 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change


  y = 2 * (x ** 2 - x) ** 2 * np.sin(p)


  r = u * (x * np.sin(p) + y * np.cos(p)) * 1.5


  h = u * (x * np.cos(p) - y * np.sin(p))


  c= plt.get_cmap('magma')


  surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,


                         cmap= c, linewidth=0, antialiased=True)


  plt.show()




  二、玫瑰花绘制—五颜六色






 import numpy as np

  import matplotlib.pyplot as plt


  from matplotlib import cm


  from mpl_toolkits.mplot3d import Axes3D


  fig = plt.figure()


  ax = fig.gca(projection='3d')


  [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 17 * np.pi - 2 * np.pi)


  p = (np.pi / 2) * np.exp(-t / (8 * np.pi))


  u = 1 - (1 - np.mod(3.6 * t, 2 * np.pi) / np.pi) ** 4 / 2


  y = 2 * (x ** 2 - x) ** 2 * np.sin(p)


  r = u * (x * np.sin(p) + y * np.cos(p))


  h = u * (x * np.cos(p) - y * np.sin(p))


  c= cm.gist_rainbow_r


  surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,


                         cmap= c, linewidth=0, antialiased=True)


  plt.show()




  三、玫瑰花绘制—粉红色





 import numpy as np

  import matplotlib.pyplot as plt


  from matplotlib import cm


  from mpl_toolkits.mplot3d import Axes3D


  fig = plt.figure()


  ax = fig.gca(projection='3d')


  [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 17 * np.pi - 2 * np.pi)


  p = (np.pi / 2) * np.exp(-t / (8 * np.pi))


  u = 1 - (1 - np.mod(3.6 * t, 2 * np.pi) / np.pi) ** 4 / 2


  y = 2 * (x ** 2 - x) ** 2 * np.sin(p)

  r = u * (x * np.sin(p) + y * np.cos(p))


  h = u * (x * np.cos(p) - y * np.sin(p))


  c= cm.get_cmap('spring_r')


  surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,


                         cmap= c, linewidth=0, antialiased=True)


  plt.show()




  四、玫瑰花绘制—红色





 # 省略了头文件,可以在之前的博客里看到

  import numpy as np


  import matplotlib.pyplot as plt


  from mpl_toolkits.mplot3d import Axes3D


  fig = plt.figure()


  ax = fig.gca(projection='3d')


  # 将相位向后移动了6*pi


  [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 20 * np.pi + 4*np.pi)


  p = (np.pi / 2) * np.exp(-t / (8 * np.pi))

  # 添加边缘扰动


  change = np.sin(15*t)/150


  # 将t的参数减少,使花瓣的角度变大


  u = 1 - (1 - np.mod(3.3 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change


  y = 2 * (x ** 2 - x) ** 2 * np.sin(p)


  r = u * (x * np.sin(p) + y * np.cos(p))


  h = u * (x * np.cos(p) - y * np.sin(p))


  c= plt.get_cmap('Reds')


  surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,


                         cmap= c, linewidth=0, antialiased=True)


  plt.show()




  五、桃花绘制





  import numpy as np

  import matplotlib.pyplot as plt


  from mpl_toolkits.mplot3d import Axes3D


  fig = plt.figure()


  ax = fig.gca(projection='3d')


  [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 6 * np.pi - 4*np.pi)


  p = (np.pi / 2) * np.exp(-t / (8 * np.pi))


  change = np.sin(10*t)/20


  u = 1 - (1 - np.mod(5.2 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change


  y = 2 * (x ** 2 - x) ** 2 * np.sin(p)


  r = u * (x * np.sin(p) + y * np.cos(p)) * 1.5


  h = u * (x * np.cos(p) - y * np.sin(p))


  c= plt.get_cmap('spring_r')


  surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,


                         cmap= c, linewidth=0, antialiased=True)


  plt.show()

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