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标题: LR的参数化问题，回放没问题，参数化报错，求救。。。 [打印本页]

作者: Jacks 时间: 2010-11-10 14:53
标题: LR的参数化问题，回放没问题，参数化报错，求救。。。
本帖最后由 Jacks 于 2010-11-10 14:54 编辑

LR的参数化问题，回放没问题，参数化报错，求救。。。小弟第一次弄C/S结构
我的脚本：
Action()
{

      lrs_create_socket("socket0", "TCP", "LocalHost=0", "RemoteHost=MJW-I-SERVER:9098", LrsLastArg);

      lrs_send("socket0", "buf0", LrsLastArg);

      lrs_receive("socket0", "buf1", LrsLastArg);

      lrs_send("socket0", "buf2", LrsLastArg);

      lrs_receive("socket0", "buf3", LrsLastArg);

      lrs_create_socket("socket1", "TCP", "LocalHost=0", "RemoteHost=MJW-I-SERVER:9098", LrsLastArg);

      lrs_send("socket1", "buf4", LrsLastArg);

      lrs_receive("socket1", "buf5", LrsLastArg);

      lrs_send("socket1", "buf6", LrsLastArg);

      lrs_receive("socket1", "buf7", LrsLastArg);

      lrs_close_socket("socket1");

      lrs_close_socket("socket0");

      lr_think_time(5);

      lrs_create_socket("socket2", "TCP", "LocalHost=0", "RemoteHost=MJW-I-SERVER:9098", LrsLastArg);

      lrs_send("socket2", "buf8", LrsLastArg);

      lrs_receive("socket2", "buf9", LrsLastArg);

      lrs_send("socket2", "buf10", LrsLastArg);

      lrs_receive("socket2", "buf11", LrsLastArg);

lr_output_message("name:%s",lr_eval_string("<name>"));

  lr_output_message("pass:%s",lr_eval_string("<pass>"));
      lrs_create_socket("socket3", "TCP", "LocalHost=0", "RemoteHost=MJW-I-SERVER:9098", LrsLastArg);

      lrs_send("socket3", "buf12", LrsLastArg);

      lrs_receive("socket3", "buf13", LrsLastArg);

      lrs_send("socket3", "buf14", LrsLastArg);

      lrs_receive("socket3", "buf15", LrsLastArg);

      lr_think_time(5);

      lrs_close_socket("socket3");

      lrs_create_socket("socket4", "TCP", "LocalHost=0", "RemoteHost=MJW-I-SERVER:9098", LrsLastArg);

      lrs_send("socket4", "buf16", LrsLastArg);

      lrs_receive("socket4", "buf17", LrsLastArg);

      lrs_send("socket4", "buf18", LrsLastArg);

      lrs_receive("socket4", "buf19", LrsLastArg);
      return 0;
}

数据的部分：
send buf10 192
      "\x06\xb9\x01"
      "l!http://tempuri.org/IUserBLL/Logi ... 8.0.18:9098/UserBLL"
      "\x05"
      "Login"
      "\x13"
      "http://tempuri.org/"
      "\x02"
      "id\bpasswordV"
      "\x02"
      "\v"
      "\x01"
      "s"
      "\x04"
      "\v"
      "\x01"
      "a"
      "\x06"
      "V\bD\n"
      "\x1e\x00"
      "偒"
      "\x01"
      "D"
      "\x1a"
      "璠y"
      "\x14"
      "珬!荂犇裕"
      "\x1a"
      "傺YD,D*"
      "\xab\x14\x01"
      "D\f"
      "\x1e\x00"
      "偒"
      "\x03\x01"
      "V"
      "\x0e"
      "B"
      "\x05"
      "\n"
      "\x07"
      "B\t"
      "\x99\x03"
      "<name>"                      //参数用户名
      "\x99\x03"
      "<pass>"                      //参数密码
      "\x01\x01\x01"

回放一次没问题，但参数化，迭代2次就报错了：Action.c(30): Error : socket2 - Invalid argument. Error code : 10022.什么原因呢？

作者: skyzhu 时间: 2010-11-10 16:01
socket2 没有关闭
迭代时又重新创建了，所以报错

作者: Jacks 时间: 2010-11-10 17:43
回复 2# skyzhu

这个解决了，但我录制一个新加用户，回放也成功了，但数据库里面为什么没有增加呢？

作者: msnshow 时间: 2010-11-12 00:04
唯一性约束

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