作者: kallinr 时间: 6 天前
SELECT city, COUNT(*) AS customer_count
FROM customers
GROUP BY city
ORDER BY customer_count DESC;作者: oliver.tang 时间: 6 天前
order by 作者: 海海豚 时间: 6 天前
SELECT city, COUNT(*) AS customer_count
FROM customers
GROUP BY city
ORDER BY customer_count DESC;作者: jingzizx 时间: 6 天前
SELECT city, COUNT(*) AS customer_count
FROM customers
GROUP BY city
ORDER BY customer_count DESC;作者: 你好浮戈 时间: 6 天前
SELECT city, COUNT(*) AS customer_count
FROM customers
GROUP BY city
ORDER BY customer_count DESC;作者: litingting0214 时间: 6 天前
SELECT city, COUNT(*) AS customer_count
FROM customers
GROUP BY city
ORDER BY customer_count DESC;