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标题: 流媒体测试中data.ws中参数化问题 [打印本页]

作者: dragon-pk    时间: 2008-8-7 10:17
标题: 流媒体测试中data.ws中参数化问题
;WSRData 2 1

send buf0 128
        "OPTIONS rtsp://192.168.0.58:554/sh.mpg RTSP/1.0\r\n"
        "CSeq: 1\r\n"
        "User-Agent: VLC media player (LIVE555 Streaming Media v2007.02.20)\r\n"
        "\r\n"

recv buf1 115
        "RTSP/1.0 200 Ok\r\n"
        "Cseq: 1\r\n"
        "Server: VLC Server\r\n"
        "Public: DESCRIBE, SETUP, TEARDOWN, PLAY, PAUSE\r\n"
        "Content-Length: 0\r\n"
        "\r\n"

send buf2 154
        "DESCRIBE rtsp://192.168.0.58:554/sh.mpg RTSP/1.0\r\n"
        "CSeq: 2\r\n"
        "Accept: application/sdp\r\n"
        "User-Agent: VLC media player (LIVE555 Streaming Media v2007.02.20)\r\n"
        "\r\n"

recv buf3 339
        "RTSP/1.0 200 OK\r\n"
        "Content-type: application/sdp\r\n"
        "Server: VLC Server\r\n"
        "Content-Length: 214\r\n"
        "Cseq: 2\r\n"
        "Cache-Control: no-cache\r\n"
        "\r\n"
        "v=0\r\n"
        "o=- 1217380334398509 2 IN IP4 192.168.0.58\r\n"
        "c=IN IP4 0.0.0.0\r\n"
        "t=0 0\r\n"
        "a=tool:vlc 0.8.6c\r\n"
        "a=range:npt=0-206.889\r\n"
        "m=video 0 RTP/AVP 33\r\n"
        "a=rtpmap:33 MP2T/90000\r\n"
        "a=control:rtsp://192.168.0.58:554/sh.mpg/trackID=0\r\n"

/*send buf4 11
        "hostIdTest"
        "\x00"

recv buf5 11
        "hostIdTest"
        "\x00"*/

send buf6 188
        "SETUP rtsp://192.168.0.58:554/sh.mpg/trackID=0 RTSP/1.0\r\n"
        "CSeq: 3\r\n"
        "Transport: RTP/AVP;unicast;client_port=24008-24009\r\n"
        "User-Agent: VLC media player (LIVE555 Streaming Media v2007.02.20)\r\n"
        "\r\n"

recv buf7 160
        "RTSP/1.0 200 OK\r\n"
        "Transport: RTP/AVP/UDP;client_port=24008-24009\r\n"
        "Server: VLC Server\r\n"
        "Content-Length: 0\r\n"
        "Cseq: 3\r\n"
        "Cache-Control: no-cache\r\n"
        "Session: 945394267\r\n"
        "\r\n"

send buf8 167
        "PLAY rtsp://192.168.0.58:554/sh.mpg RTSP/1.0\r\n"
        "CSeq: 4\r\n"
        "Session: <newsession>\r\n"
        "Range: npt=0.000-\r\n"
        "User-Agent: VLC media player (LIVE555 Streaming Media v2007.02.20)\r\n"
        "\r\n"

recv buf9 122
        "RTSP/1.0 200 OK\r\n"
        "Server: VLC Server\r\n"
        "Content-Length: 0\r\n"
        "Cseq: 4\r\n"
        "Cache-Control: no-cache\r\n"
        "Session: 945394267;timeout=5\r\n"
        "\r\n"
现在我想第一个用户执行cseq是1-4  第二个用户执行是5-8,依此类推 请问应该如何实现
请问应该如何参数化
我看了参数化选择Unique可以实现递增 不过还不是很明白,请大家帮忙呀 谢谢了
作者: aks5201314    时间: 2008-8-7 14:44
你参数化选择Unique,同时下面的复选框中选择Allocate 4 values for each vuser.注意选择参数Unique更新方式时,必须要有足够的参数可用.如果你有两个用户,那么至少要准备8个参数.




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