qtp连接oracle
本帖最后由 yidao8808 于 2011-8-22 09:59 编辑Dim Cnn
Dim Rst
Dim strCnn
Set Cnn = CreateObject("ADODB.Connection")
Set Rst =CreateObject("ADODB.Recordset")
strCnn="provider=OraOLEDB.Oracle.1;Data Source=XXX;password=XXX;User ID=XXX; Security Info=True;"
Cnn.Open strCnn
If Cnn.State=0 Then
Reporter.ReportEvent micFail,"testing","数据库连接失败"
else
Reporter.ReportEvent micPass, "testing","数据库连接成功"
End If
msgbox Cnn.State
If Cnn.Open<>0 Then
strsql="select * from pets"
Rst.Open strsql,Cnn
ydl=Rst("name")
msgbox ydl
Set Rst=nothing
Cnn.Close
End If
运行到 If Cnn.Open<>0 Then总是提示“对象打开时，不允许操作。” 求助求助。。大侠来帮忙啊:handshake Cnn.Open<>0还是Cnn.State<>0? 回复 3# Ganve_001
:L:L:L真是粗心，是Cnn.State
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