如果有一个students表,包含id、name、grade列,如何查询成绩(grade)在 80 - 90 ...
如果有一个students表,包含id、name、grade列,如何查询成绩(grade)在 80 - 90 之间的学生姓名?**** Hidden Message *****
select id,name,grade from students where grade between 80 and 90 SELECT name FROM students WHERE grade >= 80 AND grade <= 90; select id,name,grade from students where grade between 80 and 90 select id,name,grade from students where grade between 80 and 90 select id,name,grade from students where grade between 80 and 90 select id,name,grade from students where grade between 80 and 90
页:
[1]